mohon bantuannya kak
Jawab:
komposisi dan fungsi invers
f(x) = x +2
g(x) = x³ - 1
h(x) = 2x
a) rumus (hogof)⁻¹(x)
(hogof)(x) =
= h og (x +2)
= h {(x+2)² + 1}
= 2{ (x +2)³ + 1 }
= 2(x + 2)³+ 2
y = 2(x + 2)³ + 2
2(x + 2 )³ = y - 2
(x + 2)³ = (y -2) /2
[tex]\sf (x+ 2) = \sqrt[3]{\frac{y-2}{2}}[/tex]
[tex]\sf x = \sqrt[3]{\frac{y-2}{2}} - 2[/tex]
[tex]\sf (hogof)^{-1}(x) = \sqrt[3]{\dfrac{x-2}{2}} - 2[/tex]
b. (hogof)⁻¹(2) =
[tex]\sf (hogof)^{-1}(2) = \sqrt[3]{\dfrac{2-2}{2}} - 2[/tex]
= 0 - 2
= 2
[answer.2.content]
